Finding binomial and trinomial expressions using solids (Class-8, Experience- 3) - Active Math Class

NCTB Math Solution (English Version)

Finding binomial and trinomial expressions using solids (Class-8, Experience- 3)

[Exercise- Page 69]


E.3.1. Which of the following is not a binomial expression? Explain the logic behind your answer. 

a)  xy + 3x

b)  xy

c)  x + y - 1

d)  x2 - 2x + 1

e)  y2


Solution:

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E.3.2. From the binomial expressions below, separate the expressions with one variable and two variables. 

a)  x + 1

b)  3x + 5

c)  x - 3

d)  5x - 2

e)  2x + 3y

f)  x2 + 1 

g)  x2 - y

h)  x2 + y2


Solution:

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E.3.3. From the algebraic expressions below, determine the trinomial expressions of one, two and three variables respectively. 

a)  x + y + 3

b)  x2 + 3x + 5

c)  xy + z - 3

d)  5x + y2 - 2

e)  2x + 3y - z

f)  y2 - y + 1

g)  x2 - yz + 2

h)  x2 + y2 - 2


Solution:

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E.3.4. Calculate the cubes of following trinomial expressions. 

a)  x + y + 3

b)  2x + 3y - z

c)  x2 + 3x + 5

d)  xy + z - 3


Solution:

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E.3.5. Factorize the expressions using algebraic rules: 

a)  x3 + 1

b)  x3 - 1

c)  x6 - 729

d)  x3 + 3x2 + 3x + 9


Solution:

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E.3.6. In a chocolate factory, raw materials are kept in two cubic shaped containers of length 2 ft and 3 ft respectively to their full capacity. 

a) If no raw material is lost/damaged, how many chocolates of size 1” × 1” × 2” can be produced by taking all the raw materials of the two containers. 

b) If no raw material is lost/damaged, how many chocolates of size 5” × 7” × 1” can be produced by taking all the raw materials of the two containers. 

c) If 1440 chocolate bars of size 5” × 7” × 1” are produced using the raw materials of the two containers, how much of the raw materials are wasted?


Solution:

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E.3.7. Suppose Lata’s father has a fish farm. There is a pond in the farm which is 50 meters long, 40 meters wide and 5 meters deep. Keeping the volume fixed, if we want to reduce the depth by 3 meters, how long the length is needed to be increased?


Solution:

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